R-28. Ms. O'toole gave you an equation to consider:
y=5x-4
Our noticings:
*+ slope because when I graphed it- no "N"
* y-intercept is -4 (y-intercept is where the line crosses the y axis, x=0
*Slope=5 in the equation rise=5, run=1 5/1 (Rise of 5 and run of 1)
**You can get find any point on the line from the equation
y=-1/2x +3
Our Noticings:
*Slope is -1/2
*Rise is -1 and run is 2 or Slope is -1/2 and rise is 1 **The class is in disequilibrium of which one is correct.
* y-intercept is where the graph starts
*When I made the graph I got a neg. slope
